C 程序：展示基本算术运算和类型转换作用

原文：https://www.studytonight.com/c/programs/important-concepts/basic-arithmetic-operations

这里我们有两个简单的程序来展示各种基本的算术运算，以及在我们的程序中显式使用和不使用类型转换的情况下，C 语言是如何处理类型转换的。

没有类型转换的算术运算

下面是一个不用类型转换就能完成基本算术运算的程序。

#include<stdio.h>

int main()
{
    printf("\n\n\t\tStudytonight - Best place to learn\n\n\n");
    int a, b, add, subtract, multiply;
    float divide;

    printf("Enter two integers: \n");
    scanf("%d%d", &a, &b);

    add = a+b;
    subtract = a-b;
    multiply = a*b;
    divide = a/b;

    printf("\nAddition of the numbers = %d\n", add);
    printf("Subtraction of 2nd number from 1st = %d\n", subtract);
    printf("Multiplication of the numbers = %d\n", multiply);
    printf("Dividing 1st number from 2nd = %f\n", divide);
    printf("\n\n\t\t\tCoding is Fun !\n\n\n");
    return 0;
}

输出:

具有类型转换的算术运算

C 语言确实隐式处理类型转换，但是用户也可以在他们的程序中处理它。

下面是一个使用类型转换执行基本算术运算的简单程序。

#include<stdio.h>

int main()
{
    printf("\n\n\t\tStudytonight - Best place to learn\n\n\n");

    int a, b, add, subtract, multiply, remainder;
    float divide;

    printf("Enter two integers: \n");
    scanf("%d%d", &a, &b);

    add = a+b;
    subtract = a-b;
    multiply = a*b;
    divide = a/(float)b;
    remainder = a%b;

    printf("\n\nAddition of the numbers = %d\n", add);
    printf("\nSubtraction of 2nd number from 1st = %d\n", subtract);
    printf("\nMultiplication of the numbers = %d\n", multiply);
    printf("\nDividing 1st number from 2nd = %f\n", divide);
    printf("\nRemainder on Dividing 1st number by 2nd is %d\n", remainder);
    printf("\n\n\t\t\tCoding is Fun !\n\n\n");
    return 0;
}

输出: