C++ 程序：按引用调用

原文：https://www.studytonight.com/cpp-programs/cpp-call-by-reference-program

大家好！

在本教程中，我们将以 C++ 编程语言学习通过引用调用函数调用的工作原理。

按引用调用函数调用:

在这种类型的函数调用中，位置或变量的地址被传递给，而不是变量本身的值。

要了解这个概念的更多信息，请访问https://www . study south . com/CPP/call-by-value-and-reference . PHP，我们已经解释了按值调用和按引用调用函数调用之间的区别。

为了更好地理解，请参考下面给出的注释良好的代码。

代号:

#include <iostream>
#include<vector>
using namespace std;

//Function prototyping as defined after it is being called.  
// It denotes that the method sumOf() takes two parameters which are pointer to an int and returns int
int sumOf(int *, int *);

int main()
{
    cout << "\n\nWelcome to Studytonight :-)\n\n\n";
    cout << " =====  Program to demonstrate the working of Pass By Reference Function call, in CPP  ===== \n\n";

    //variable declaration
    int num1 = 0, num2 = 0, addition=0;

    cout << "Enther the two numbers you want to add : \n\n";
    cin >> num1;
    cin >> num2;

    /*
    Demonstrating Multi-line Commenting:
        Passing the values stored in the variables num1 and num2 as a parameter to function sumOf().
        The value returned by the function is stored in the variable output
    */

   //It is not always necessary to store the returned value into a variable as it can be directly used as demonstrted below
    cout << "\n\nThe Sum of the two numbers " << num1 << " and " << num2 << ", returned by the function sumOf(), is = " << sumOf(&num1, &num2);

    cout << "\n\n\n";

    return 0;
}

// Defining the function sumOf(a,b) which is called by Passing Values and returns the sum of a and b
int sumOf(int *n1, int *n2)
{
    int sum;
    //Computing the addition of the two values the function is called with
    sum = *n1 + *n2;

    //Returning the addition to the point where this function is called from
    return sum;
}

输出:

我们希望这篇文章能帮助你更好地理解 C++ 中引用调用的概念。如有任何疑问，请随时通过下面的评论区联系我们。

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